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1,�����ͳ�
����ؓ(f��)�� q=1.0m3/m2..h
ÿС�r(sh��)̎����ˮ��Q=7/24=0.29m3/h
S����e=0.29/1=0.29m2
�{(di��o)��(ji��)һ���ˮ��v=7m3
�O(sh��)Ӌ(j��)�ߴ��V=5×2×1.8=18m3
2������������
����ؓ(f��)�� q=1.0m3/m2..h
ÿС�r(sh��)̎����ˮ��Q=7/24=0.29m3/h
S����e=0.29/1=0.29m2
�O(sh��)Ӌ(j��)�ߴ��V=2×2×4=16m3
3,���{(di��o)��(ji��)��ϳ�
�{(di��o)��(ji��)10С�r(sh��)�����a(ch��n)�Uˮ
ÿС�r(sh��)�M(j��n)ˮ��Q1=281/24 =11.7 m3/h
V= Q1×10=117 m3
�O(sh��)Ӌ(j��)�ߴ��V=8×5×3.3=132m3
4������������
ȡ�ݷeؓ(f��)�ɞ�2.5kgBOD5/m3·d,��B/C=0.65,��CODcr�s��6000mg/l��
ˮ����281 m3/d
V = COD×0.65×ˮ��/(2.5KgBOD5/m3.d)
= 6×0.65×281/2.5
= 438.36m3 (632.25)
�O(sh��)Ӌ(j��)�ߴ��?8000×10(326.56)
5,��SBR��ˮ��
ͣ���r(sh��)�g10С�r(sh��),��ˮ��281m3/d
V= Q1×10=281×10÷24=117 m3
�O(sh��)Ӌ(j��)�ߴ��V=9×3×5.5=148.5m3
6��SBR����(y��ng)��
�M(j��n)��SBR����(y��ng)�ص�CODcr�s��1500mg/l��B/C=0.65
V = (COD×B/C×ˮ��)/(0.095×3.5)
= (1.5×0.65×281)/(0.095×3.5)
= 824m3 (950)
��2��(g��)SBR����(y��ng)��,����(g��)SBR����(y��ng)���O(sh��)Ӌ(j��)�ߴ��V=14×6×5.5=462m3
7������s��
�M(j��n)������ص�ˮ�|(zh��)COD���1500mg/l,ˮ��281m3/d,��1KgCOD�a(ch��n)��0.5Kg�������࣬��s������ຬˮ�ʞ�99.7%
һ�칲�a(ch��n)������=1.5×0.5×281= 210.75Kg
������ˮ���� =210.75÷0.003÷1000=70.25m3/d
����ؓ(f��)��ȡ4.5m3/m2.d
S����e=70.25/4.5=15.6m2
�O(sh��)Ӌ(j��)�ߴ��V=4×4×5=80m3
8,���L(f��ng)�C(j��)
�������M(j��n)ˮˮ�|(zh��)COD�s1500mg/L,ˮ��281m3/d,��B/C����0.65����ˮ�Ȟ�40,��
�L(f��ng)��Q=(COD×B/C×��ˮ��×ˮ��)/(60min×24С�r(sh��)×�L(f��ng)�C(j��)��(sh��)��)
=(1.5×0.65×40×281)/(60×24×1)
= 7.61m3/min(8.78)
���~�_���L(f��ng)�C(j��)���_
Q=4.0m3/min P=58.8Kpa N=7.5Kw
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